Ravens Raiders Football

Las Vegas Raiders defensive end Maxx Crosby (98) celebrates after a play against the Baltimore Ravens during the first half of an NFL football game, Monday, Sept. 13, 2021, in Las Vegas. (AP Photo/Rick Scuteri)

LAS VEGAS (FOX5) -- After an impressive and exciting overtime win by the Raiders, one of its players earned the honor of being named the AFC's Defensive Player of the Week.

Raiders defensive end Maxx Crosby had six tackles, two sacks and two tackles for loss in the overtime win over the Baltimore Ravens on Monday Night Football.

It's the second time Crosby has ever been named Defensive Player of the Week.

On Sunday, the Raiders will head east to take on the Pittsburgh Steelers at 10 a.m.

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